8x^2 - 2x = 1?

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Asked 9/21/2012 7:49:29 AM

Updated 7/18/2014 4:22:15 AM

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This conversation has been flagged as incorrect.

Edited by andrewpallarca [7/18/2014 4:20:27 AM], Flagged by andrewpallarca [7/18/2014 4:22:15 AM]

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Loula|Points 1133|

Question

Asked 9/21/2012 7:49:29 AM

Updated 7/18/2014 4:22:15 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Edited by andrewpallarca [7/18/2014 4:20:27 AM], Flagged by andrewpallarca [7/18/2014 4:22:15 AM]

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8x^2 - 2x = 1;

8x^2 - 2x - 1= 0;

(4x + 1)(2x - 1) = 0

(4x + 1) = 0; 4x = -1, x = -1/4 or (2x - 1) = 0; 2x = 1; x = 1/2

Solution set: {x = -1/4, x = 1/2}

8x^2 - 2x - 1= 0;

(4x + 1)(2x - 1) = 0

(4x + 1) = 0; 4x = -1, x = -1/4 or (2x - 1) = 0; 2x = 1; x = 1/2

Solution set: {x = -1/4, x = 1/2}

Added 7/18/2014 4:22:12 AM

This answer has been confirmed as correct and helpful.

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Updated 11/18/2017 12:50:28 AM

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Added 11/18/2017 12:50:28 AM

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